enrich時可以發起一個子流程，取得結果后再設置回當前的對象中。
package org.springframework.integration.stackoverflow.enricher;
import java.util.List;
import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.Bean;
import org.springframework.http.HttpMethod;
import org.springframework.integration.dsl.IntegrationFlow;
import org.springframework.integration.dsl.IntegrationFlows;
import org.springframework.integration.dsl.Transformers;
import org.springframework.integration.http.dsl.Http;
import org.springframework.web.client.RestTemplate;
@SpringBootApplication
public class SpringIntegrationEnricherApplication {
public static void main(String[] args) {
SpringApplication.run(SpringIntegrationEnricherApplication.class, args);
}
@Bean
public IntegrationFlow jsonEnricherFlow(RestTemplate restTemplate) {
return IntegrationFlows.from(Function.class)
.transform(Transformers.fromJson(Map.class))
.enrich((enricher) -> enricher
.<Map<String, ?>>requestPayload((message) ->
((List<?>) message.getPayload().get("attributeIds"))
.stream()
.map(Object::toString)
.collect(Collectors.joining(",")))
.requestSubFlow((subFlow) ->
subFlow.handle(
Http.outboundGateway("/attributes?id={ids}", restTemplate)
.httpMethod(HttpMethod.GET)
.expectedResponseType(Map.class)
.uriVariable("ids", "payload")))
.propertyExpression("attributes", "payload.attributes"))
.<Map<String, ?>, Map<String, ?>>transform(
(payload) -> {
payload.remove("attributeIds");
return payload;
})
.transform(Transformers.toJson())
.get();
}
}
https://stackoverflow.com/questions/58205432/spring-integration-enrich-transform-message-using-rest-callhttps://www.tabnine.com/web/assistant/code/rs/5c781b6ae70f87000197ab9f#L312