Let's take a look at the following code:
public Class Program{
public static void main(String[] args){
int i = 0;
int[] a = {1,2};
a[i] = i = 2;
System.out.println(i + " " + a[0]+ " "+a[1]);
}
}
What is the output from the above code?
The output is:
2 2 2
You may raise some questions: "When does i get a value 2?",
"Why doesn't it use the same value (i=2) for a[i]
(which should actually give an ArrayOutOfBoundsException
Exception)?", and so on.
The reason no ArrayIndexOutOfBoundsException is thrown is
because each of the operands is evaluated from left to right. Basically
the array reference is evaluated first then the rest of the expression
is done according to the rules in the
posted on 2010-07-08 14:25 gembin 閱讀(438) 評論(0) 編輯 收藏 所屬分類: JavaSE