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    泥巴麒麟的BLOG

    shenAwesome@hotmail.com 縱不能,將醉做生涯,休拘束

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      195 Posts :: 2 Stories :: 80 Comments :: 0 Trackbacks

    工作需要,寫了些ajax用于驗證???

    摘抄一下:

    action中:
    ??
    ? public class CheckIPAction extends Action {
    ????? public ActionForward execute(ActionMapping maping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception {
    ??????? String message = "hi";
    ???????
    ??????? response.setContentType("application/x-www-form-urlencoded;charset=UTF-8");
    ??????? response.getWriter().write(message);
    ??????? return null;
    ????? }
    ??? }


    ?? jsp中的<script>里:
    ???????? //固定的,可寫個js
    ???????? function executeXhr(callback, url,info) {
    ???????? if (window.XMLHttpRequest) {
    ??????????? req = new XMLHttpRequest();
    ??????????? req.onreadystatechange = callback;
    ??????????? req.open("POST", url, true);
    ??????????? req.setRequestHeader("Content-Length",info.length);????
    ??????????? req.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
    ??????????? req.send("info");
    ???????? } else if (window.ActiveXObject) {
    ??????????? req = new ActiveXObject("Microsoft.XMLHTTP");
    ??????????? if (req) {
    ????????????? req.onreadystatechange = callback;
    ????????????? req.open("POST", url, true);
    ????????????? req.setRequestHeader("Content-Length",info.length);???
    ????????????? req.setRequestHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
    ????????????? req.send(info);
    ??????????? }
    ????????? }
    ?????? }
    ?????? function processAjaxResponse() {
    ??????? if (req.readyState == 4) {
    ??????????? // only if "OK"
    ??????????? if (req.status == 200) {
    ?????????????? var res =? req.responseText;
    ?????????????? doResponse(res);
    ??????????? } else {
    ??????????????? alert("There was a problem retrieving the XML data:\n" +
    ??????????????? req.statusText);
    ??????????? }
    ???????? }
    ?????? }
    ???????
    ?????? //下面是需要修改的
    ?????? function sendRequest(){
    ????????? var url = "./checkIPAction.do";
    ????????? var callback = processAjaxResponse;
    ????????? var queryStr = "ips=1";
    ????????? executeXhr(callback, url,queryStr);??????
    ?????? }
    ?????? function doResponse(response){
    ????????????? msg.innerHTML = response;
    ?????? }

    posted on 2007-03-02 17:45 泥巴麒麟 閱讀(137) 評論(0)  編輯  收藏

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