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數(shù)據(jù)統(tǒng)計(jì),棧操作

// 棧四個(gè)方法分別是:
?2

???? // --判斷棧是否為空
?3

???? // --獲得棧頂數(shù)據(jù)項(xiàng)而沒有刪除
?4

???? // --任意數(shù)據(jù)項(xiàng)入棧
?5

???? // --獲得并刪除棧頂元素
?6

????
?7

???? public ? interface ?CountStack?
?8

???? {?
?9

????????
10

???????? boolean ?isEmpty?();
11

????????
12

????????Object?peek?();?
13

????????
14

???????? void ?push?(Object?o);?
15

????????
16

????????Object?pop?();?
17

????}
18

// 實(shí)現(xiàn)接口
20

public ? class ?CountViewArrayStack? implements ?CountViewStack {
22

????
23

???????? private ? int ?top? = ? - 1 ;?
24

????
25

???????? private ?Object[]?stack;?
26

???????? public ?CountViewArrayStack( int ?maxElements)?
28

????
29

???????? {???
30

????????????stack? = ? new ?Object[maxElements];
31

????????} ?
32

????????
33

???????? public ? boolean ?isEmpty?()
34

???????? {
35

???????????? return ?top? == ? - 1 ;
36

????????}
37

????????
38

???????? public ?Object?peek()?
39

????
40

???????? {?
41

???????????? if ?(top? < ? 0 )??
42

???????????? throw ? new ?java.util.EmptyStackException();?
43

???????????? return ?stack[top];
44

????????} ?
45

???????? public ? void ?push(Object?o)?
47

????
48

???????? {?
49

???????????? if ?(top? == ?stack.length? - ? 1 )?????
50

???????????? throw ? new ?FullViewStackException();?
51

????????????stack[ ++ top]? = ?o;
52

????????} ?
53

???????? public ?Object?pop()?
55

????
56

???????? {?
57

???????????? if ?(top? < ? 0 )??
58

???????????? throw ? new ?java.util.EmptyStackException();?
59

???????????? return ?stack[top -- ];?
60

????????}
61

}

posted on 2007-09-26 09:04 crazy 閱讀(168) 評(píng)論(0) 編輯收藏所屬分類: java

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