Syntax
using [typename][::] nested-name-specifier unqualified-id
using :: unqualified-id
The using declaration introduces a name into the declarative region in which the using declaration appears. The name becomes a synonym for an entity declared elsewhere. It allows an individual name from a specific namespace to be used without explicit qualification. This is in contrast to the using directive, which allows all the names in a namespace to be used without qualification. See using Directive for more information.
A using-declaration can be used in a class definition. For example:
class B
{
void f(char);
void g(char);
};
class D : B
{
using B::f;
void f(int) { f('c'); } // calls B::f(char)
void g(int) { g('c'); } // recursively calls D::g(int)
// only B::f is being used
};
When used to declare a member, a using-declaration must refer to a member of a base class. For example:
class C
{
int g();
};
class D2 : public B
{
using B::f; // ok: B is a base of D2
using C::g; // error: C isn't a base of D2
};
Members declared with a using-declaration can be referenced using explicit qualification. The :: prefix refers to the global namespace. For example:
void f();
namespace A
{
void g();
}
namespace X
{
using ::f; // global f
using A::g; // A's g
}
void h()
{
X::f(); // calls ::f
X::g(); // calls A::g
}
Just as with any declaration, a using-declaration can be used repeatedly only where multiple declarations are allowed. For example:
namespace A
{
int i;
}
void f()
{
using A::i;
using A::i; // ok: double declaration
}
class B
{
protected:
int i;
};
class X : public B
{
public:
using B::i;
using B::i; // error: class members cannot be multiply declared
};
When a using-declaration is made, the synonym created by the declaration refers only to definitions that are valid at the point of the using-declaration. Definitions added to a namespace after the using-declaration are not valid synonyms. For example:
namespace A
{
void f(int);
}
using A::f; // f is a synonym for A::f(int) only
namespace A
{
void f(char);
}
void f()
{
f('a'); // refers to A::f(int), even though A::f(char) exists
}
void b()
{
using A::f; // refers to A::f(int) AND A::f(char)
f('a'); // calls A::f(char);
}
A name defined by a using-declaration is an alias for its original name. It does not affect the type, linkage or other attributes of the original declaration.
If a set of local declarations and using-declarations for a single name are given in a declarative region, they must all refer to the same entity, or they must all refer to functions. For example:
namespace B
{
int i;
void f(int);
void f(double);
}
void g()
{
int i;
using B::i; // error: i declared twice
void f(char);
using B::f; // ok: each f is a function
}
In the example above, the using B::i statement causes a second int i to be declared in the g() function. The using B::f statement does not conflict with the f(char) function because the function names introduced by B::f have different parameter types.
A local function declaration cannot have the same name and type as a function introduced by a using-declaration. For example:
namespace B
{
void f(int);
void f(double);
}
namespace C
{
void f(int);
void f(double);
void f(char);
}
void h()
{
using B::f; // introduces B::f(int) and B::f(double)
using C::f; // C::f(int), C::f(double), and C::f(char)
f('h'); // calls C::f(char)
f(1); // error: ambiguous: B::f(int) or C::f(int)?
void f(int); // error: conflicts with B::f(int) and C::f(int)
}
When a using-declaration introduces a name from a base class into a derived class scope, member functions in the derived class override virtual member functions with the same name and argument types in the base class. For example:
struct B
{
virtual void f(int);
virtual void f(char);
void g(int);
void h(int);
};
struct D : B
{
using B::f;
void f(int); // ok: D::f(int) overrides B::f(int)
using B::g;
void g(char); // ok: there is no B::g(char)
using B::h;
void h(int); // error: D::h(int) conflicts with B::h(int)
// B::h(int) is not virtual
};
void f(D* pd)
{
pd->f(1); // calls D::f(int)
pd->f('a'); // calls B::f(char)
pd->g(1); // calls B::g(int)
pd->g('a'); // calls D::g(char)
}
All instances of a name mentioned in a using-declaration must be accessible. In particular, if a derived class uses a using-declaration to access a member of a base class, the member name must be accessible. If the name is that of an overloaded member function, then all functions named must be accessible. For example:
class A
{
private:
void f(char);
public:
void f(int);
protected:
void g();
};
class B : public A
{
using A::f; // error: A::f(char) is inaccessible
public:
using A::g; // B::g is a public synonym for A::g
};
from: http://msdn.microsoft.com/library/default.asp?url=/library/en-us/vccelng/htm/tions_43.asp