??? Java 1.5（或者說Java 5.0、Tiger）給我們帶來了很多新特性，這些新特性都有哪些呢？讓我們拭目以待。今天，我們先來看看Arrays類，一個全部由靜態(tài)方法構成的類，提供了許多有用的操作數(shù)組的方法。
我們先來看一個示例：
package
?com.jiang.tiger.chap1;
import
?java.util.Arrays;
 
public
?
class
?ArraysTester?
{
 ??
private
?
int
[]?ar;
  ??
public
?ArraysTester(
int
?numValues)?
{
????ar?
=
?
new
?
int
[numValues];
????
for
?(
int
?i
=
0
;?i?
<
?ar.length;?i
++
)?
{
??????ar[i]?
=
?(
1000
?
-
?(
300
?
+
?i));
 ????}
??}
??
public
?
int
[]?get(?)?
{
????
return
?ar;
??}
??
public
?
static
?
void
?main(String[]?args)?
{
????ArraysTester?tester?
=
?
new
?ArraysTester(
50
);
????
int
[]?myArray?
=
?tester.get(?);
????
//
?比較兩個數(shù)組
????
int
[]?myOtherArray?
=
?tester.get().clone(?);
????
if
?(Arrays.equals(myArray,?myOtherArray))?
{
??????System.out.println(
"
The?two?arrays?are?equal!
"
);
????}
?
else
?
{
??????System.out.println(
"
The?two?arrays?are?not?equal!
"
);
????}
????
//
?用指定的值填充數(shù)組
????Arrays.fill(myOtherArray,?
2
,?
10
,?
new
?Double(Math.PI).intValue(?));
????myArray[
30
]?
=
?
98
;
????
????
//
?打印無序數(shù)組
????System.out.println(
"
Here's?the?unsorted?array
"
);
????System.out.print(Arrays.toString(myArray));
????System.out.println(?);
????
//
?數(shù)組排序
????Arrays.sort(myArray);
????
//
?打印有序數(shù)組
????System.out.println(
"
Here's?the?sorted?array
"
);
????System.out.print(Arrays.toString(myArray));
????System.out.println(?);
????
//
?用二分搜索法查找指定的值。
????
int
?index?
=
?Arrays.binarySearch(myArray,?
98
);
????System.out.println(
"
98?is?located?in?the?array?at?index?
"
?
+
?index);
????
//
數(shù)組“深層次內(nèi)容”的字符串表示形式，簡而言之，將多維數(shù)組所有元素轉換為字符串。
????String[][]?ticTacToe?
=
?
{?
{
"
X
"
,?
"
O
"
,?
"
O
"
}
,
?????????????????????????????
{
"
O
"
,?
"
X
"
,?
"
X
"
}
,
?????????????????????????????
{
"
X
"
,?
"
O
"
,?
"
X
"
}
}
;
????System.out.println(Arrays.deepToString(ticTacToe));
?
????String[][]?ticTacToe2?
=
?
{?
{
"
O
"
,?
"
O
"
,?
"
X
"
}
,
??????????????????????????????
{
"
O
"
,?
"
X
"
,?
"
X
"
}
,
??????????????????????????????
{
"
X
"
,?
"
O
"
,?
"
X
"
}
}
;
????String[][]?ticTacToe3?
=
?
{?
{
"
X
"
,?
"
O
"
,?
"
O
"
}
,
??????????????????????????????
{
"
O
"
,?
"
X
"
,?
"
X
"
}
,
??????????????????????????????
{
"
X
"
,?
"
O
"
,?
"
X
"
}
}
;
????
????
//
比較兩個數(shù)組是否“深層次相等”，適用于任何維次的數(shù)組
????
if
?(Arrays.deepEquals(ticTacToe,?ticTacToe2))?
{
??????System.out.println(
"
Boards?1?and?2?are?equal.
"
);
????}
?
else
?
{
??????System.out.println(
"
Boards?1?and?2?are?not?equal.
"
);
????}
????
if
?(Arrays.deepEquals(ticTacToe,?ticTacToe3))?
{
??????System.out.println(
"
Boards?1?and?3?are?equal.
"
);
????}
?
else
?
{
??????System.out.println(
"
Boards?1?and?3?are?not?equal.
"
);
????}
????
????System.out.println(
"
Here's?the?array?of?the?ArrayTester
"
);
????System.out.print(Arrays.toString(tester.get()));
????System.out.println(?);
????
????System.out.println(
"
Here's?myArray
"
);
????System.out.print(Arrays.toString(myArray));
????System.out.println(?);
????
????System.out.println(
"
Here's?myOtherArray
"
);
????System.out.print(Arrays.toString(myOtherArray));
????System.out.println(?);
????
????Object[]?a?
=
?
new
?Object[
2
];
????a[
0
]?
=
?
1
;
????a[
1
]?
=
?a;
????System.out.println(Arrays.deepHashCode(a));
??}
 }
下面再看看輸出：
The?two?arrays?are?equal!
Here's?the?unsorted?array
[
700,?699,?698,?697,?696,?695,?694,?693,?692,?691,?690,?689,?688,?687,?686,?685,?684,?683,?682,?681,?680,?679,?678,?677,?676,?675,?674,?673,?672,?671,?98,?669,?668,?667,?666,?665,?664,?663,?662,?661,?660,?659,?658,?657,?656,?655,?654,?653,?652,?651
]
Here's?the?sorted?array
[
98,?651,?652,?653,?654,?655,?656,?657,?658,?659,?660,?661,?662,?663,?664,?665,?666,?667,?668,?669,?671,?672,?673,?674,?675,?676,?677,?678,?679,?680,?681,?682,?683,?684,?685,?686,?687,?688,?689,?690,?691,?692,?693,?694,?695,?696,?697,?698,?699,?700
]
98
?is?located?in?the?array?at?index?
0
[
[X,?O,?O
]
,
?
[
O,?X,?X
]
,
?
[
X,?O,?X
]
]
Boards?
1
?and?
2
?are?not?equal.
Boards?
1
?and?
3
?are?equal.
Here's?the?array?of?the?ArrayTester
[
98,?651,?652,?653,?654,?655,?656,?657,?658,?659,?660,?661,?662,?663,?664,?665,?666,?667,?668,?669,?671,?672,?673,?674,?675,?676,?677,?678,?679,?680,?681,?682,?683,?684,?685,?686,?687,?688,?689,?690,?691,?692,?693,?694,?695,?696,?697,?698,?699,?700
]
Here's?myArray
[
98,?651,?652,?653,?654,?655,?656,?657,?658,?659,?660,?661,?662,?663,?664,?665,?666,?667,?668,?669,?671,?672,?673,?674,?675,?676,?677,?678,?679,?680,?681,?682,?683,?684,?685,?686,?687,?688,?689,?690,?691,?692,?693,?694,?695,?696,?697,?698,?699,?700
]
Here's?myOtherArray
[
700,?699,?3,?3,?3,?3,?3,?3,?3,?3,?690,?689,?688,?687,?686,?685,?684,?683,?682,?681,?680,?679,?678,?677,?676,?675,?674,?673,?672,?671,?670,?669,?668,?667,?666,?665,?664,?663,?662,?661,?660,?659,?658,?657,?656,?655,?654,?653,?652,?651
]
Exception?in?thread?
"
main
"
?java.lang.StackOverflowError
????at?java.util.Arrays.deepHashCode(Unknown?Source)...
上面的程序使用了Arrays類的大多數(shù)方法，下面我們就來看看Arrays到底為我們帶來了哪些有用的方法：
1. asList：將指定的數(shù)組轉換為List；
2. binarySearch：采用二分搜索方法從數(shù)組中查找指定的值
3. deepEquals：比較兩個數(shù)組是否“深層次相等”，5.0引入
4. deepHashCode：計算數(shù)組的“深層次哈希碼”，5.0引入
5. deepToString：將數(shù)組轉換為字符串，5.0引入
6. equals：比較兩個數(shù)組是否相等
7. fill：用指定值填充數(shù)組
8. hashCode：計算數(shù)組的哈希值，5.0引入
9. sort：對數(shù)組排序
10. toString：將數(shù)組轉換為字符串，5.0引入。
上面的方法中除了4、5、6外，其余方法都比較簡單。4、5、6三個方法主要用來操作多維數(shù)組，如果有些數(shù)組的元素類型本身也是數(shù)組，它們會對該元素也調(diào)用相同的方法，直至最終沒有數(shù)組元素的類型為數(shù)組。這三個方法功能十分強大，但有一點需要注意：千萬不要將自身作為數(shù)組元素，例如上面示例中的a[1]=a，這樣會導致無限循環(huán)，最終導致棧溢出。
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