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    即使世界明天毀滅,我也要在今天種下我的葡萄樹(shù)。
    posts - 112, comments - 14, trackbacks - 0, articles - 11

    ORACLE函數(shù)大全

    Posted on 2006-08-09 22:17 閱讀(173) 評(píng)論(0)  編輯  收藏
    SQL中的單記錄函數(shù)
    1.ASCII
    返回與指定的字符對(duì)應(yīng)的十進(jìn)制數(shù);
    SQL> select ascii('A') A,ascii('a') a,ascii('0') zero,ascii(' ') space from dual;

    ??????? A???????? A????? ZERO???? SPACE
    --------- --------- --------- ---------
    ?????? 65??????? 97??????? 48??????? 32


    2.CHR
    給出整數(shù),返回對(duì)應(yīng)的字符;
    SQL> select chr(54740) zhao,chr(65) chr65 from dual;

    ZH C
    -- -
    趙 A

    3.CONCAT
    連接兩個(gè)字符串;
    SQL> select concat('010-','88888888')||'轉(zhuǎn)23'? 高乾競(jìng)電話(huà) from dual;

    高乾競(jìng)電話(huà)
    ----------------
    010-88888888轉(zhuǎn)23

    4.INITCAP
    返回字符串并將字符串的第一個(gè)字母變?yōu)榇髮?xiě);
    SQL> select initcap('smith') upp from dual;

    UPP
    -----
    Smith


    5.INSTR(C1,C2,I,J)
    在一個(gè)字符串中搜索指定的字符,返回發(fā)現(xiàn)指定的字符的位置;
    C1??? 被搜索的字符串
    C2??? 希望搜索的字符串
    I???? 搜索的開(kāi)始位置,默認(rèn)為1
    J???? 出現(xiàn)的位置,默認(rèn)為1
    SQL> select instr('oracle traning','ra',1,2) instring from dual;

    ?INSTRING
    ---------
    ??????? 9


    6.LENGTH
    返回字符串的長(zhǎng)度;
    SQL> select name,length(name),addr,length(addr),sal,length(to_char(sal)) from gao.nchar_tst;

    NAME?? LENGTH(NAME) ADDR???????????? LENGTH(ADDR)?????? SAL LENGTH(TO_CHAR(SAL))
    ------ ------------ ---------------- ------------ --------- --------------------
    高乾競(jìng)??????????? 3 北京市海錠區(qū)??????????????? 6?? 9999.99??????????????????? 7

    ?

    7.LOWER
    返回字符串,并將所有的字符小寫(xiě)
    SQL> select lower('AaBbCcDd')AaBbCcDd from dual;

    AABBCCDD
    --------
    aabbccdd


    8.UPPER
    返回字符串,并將所有的字符大寫(xiě)
    SQL> select upper('AaBbCcDd') upper from dual;

    UPPER
    --------
    AABBCCDD

    ?

    9.RPAD和LPAD(粘貼字符)
    RPAD? 在列的右邊粘貼字符
    LPAD? 在列的左邊粘貼字符
    SQL> select lpad(rpad('gao',10,'*'),17,'*')from dual;

    LPAD(RPAD('GAO',1
    -----------------
    *******gao*******
    不夠字符則用*來(lái)填滿(mǎn)


    10.LTRIM和RTRIM
    LTRIM? 刪除左邊出現(xiàn)的字符串
    RTRIM? 刪除右邊出現(xiàn)的字符串
    SQL> select ltrim(rtrim('?? gao qian jing?? ',' '),' ') from dual;

    LTRIM(RTRIM('
    -------------
    gao qian jing


    11.SUBSTR(string,start,count)
    取子字符串,從start開(kāi)始,取count個(gè)
    SQL> select substr('13088888888',3,8) from dual;

    SUBSTR('
    --------
    08888888


    12.REPLACE('string','s1','s2')
    string?? 希望被替換的字符或變量
    s1?????? 被替換的字符串
    s2?????? 要替換的字符串
    SQL> select replace('he love you','he','i') from dual;

    REPLACE('H
    ----------
    i love you


    13.SOUNDEX
    返回一個(gè)與給定的字符串讀音相同的字符串
    SQL> create table table1(xm varchar(8));
    SQL> insert into table1 values('weather');
    SQL> insert into table1 values('wether');
    SQL> insert into table1 values('gao');

    SQL> select xm from table1 where soundex(xm)=soundex('weather');

    XM
    --------
    weather
    wether


    14.TRIM('s' from 'string')
    LEADING?? 剪掉前面的字符
    TRAILING? 剪掉后面的字符
    如果不指定,默認(rèn)為空格符

    15.ABS
    返回指定值的絕對(duì)值
    SQL> select abs(100),abs(-100) from dual;

    ?ABS(100) ABS(-100)
    --------- ---------
    ????? 100?????? 100


    16.ACOS
    給出反余弦的值
    SQL> select acos(-1) from dual;

    ?ACOS(-1)
    ---------
    3.1415927


    17.ASIN
    給出反正弦的值
    SQL> select asin(0.5) from dual;

    ASIN(0.5)
    ---------
    .52359878


    18.ATAN
    返回一個(gè)數(shù)字的反正切值
    SQL> select atan(1) from dual;

    ? ATAN(1)
    ---------
    .78539816


    19.CEIL
    返回大于或等于給出數(shù)字的最小整數(shù)
    SQL> select ceil(3.1415927) from dual;

    CEIL(3.1415927)
    ---------------
    ????????????? 4


    20.COS
    返回一個(gè)給定數(shù)字的余弦
    SQL> select cos(-3.1415927) from dual;

    COS(-3.1415927)
    ---------------
    ???????????? -1


    21.COSH
    返回一個(gè)數(shù)字反余弦值
    SQL> select cosh(20) from dual;

    ?COSH(20)
    ---------
    242582598


    22.EXP
    返回一個(gè)數(shù)字e的n次方根
    SQL> select exp(2),exp(1) from dual;

    ?? EXP(2)??? EXP(1)
    --------- ---------
    7.3890561 2.7182818


    23.FLOOR
    對(duì)給定的數(shù)字取整數(shù)
    SQL> select floor(2345.67) from dual;

    FLOOR(2345.67)
    --------------
    ????????? 2345


    24.LN
    返回一個(gè)數(shù)字的對(duì)數(shù)值
    SQL> select ln(1),ln(2),ln(2.7182818) from dual;

    ??? LN(1)???? LN(2) LN(2.7182818)
    --------- --------- -------------
    ??????? 0 .69314718???? .99999999


    25.LOG(n1,n2)
    返回一個(gè)以n1為底n2的對(duì)數(shù)
    SQL> select log(2,1),log(2,4) from dual;

    ?LOG(2,1)? LOG(2,4)
    --------- ---------
    ??????? 0???????? 2


    26.MOD(n1,n2)
    返回一個(gè)n1除以n2的余數(shù)
    SQL> select mod(10,3),mod(3,3),mod(2,3) from dual;

    MOD(10,3)? MOD(3,3)? MOD(2,3)
    --------- --------- ---------
    ??????? 1???????? 0???????? 2


    27.POWER
    返回n1的n2次方根
    SQL> select power(2,10),power(3,3) from dual;

    POWER(2,10) POWER(3,3)
    ----------- ----------
    ?????? 1024???????? 27


    28.ROUND和TRUNC
    按照指定的精度進(jìn)行舍入
    SQL> select round(55.5),round(-55.4),trunc(55.5),trunc(-55.5) from dual;

    ROUND(55.5) ROUND(-55.4) TRUNC(55.5) TRUNC(-55.5)
    ----------- ------------ ----------- ------------
    ???????? 56????????? -55????????? 55????????? -55


    29.SIGN
    取數(shù)字n的符號(hào),大于0返回1,小于0返回-1,等于0返回0
    SQL> select sign(123),sign(-100),sign(0) from dual;

    SIGN(123) SIGN(-100)?? SIGN(0)
    --------- ---------- ---------
    ??????? 1???????? -1???????? 0


    30.SIN
    返回一個(gè)數(shù)字的正弦值
    SQL> select sin(1.57079) from dual;

    SIN(1.57079)
    ------------
    ?????????? 1


    31.SIGH
    返回雙曲正弦的值
    SQL> select sin(20),sinh(20) from dual;

    ? SIN(20)? SINH(20)
    --------- ---------
    .91294525 242582598


    32.SQRT
    返回?cái)?shù)字n的根
    SQL> select sqrt(64),sqrt(10) from dual;

    ?SQRT(64)? SQRT(10)
    --------- ---------
    ??????? 8 3.1622777


    33.TAN
    返回?cái)?shù)字的正切值
    SQL> select tan(20),tan(10) from dual;

    ? TAN(20)?? TAN(10)
    --------- ---------
    2.2371609 .64836083


    34.TANH
    返回?cái)?shù)字n的雙曲正切值
    SQL> select tanh(20),tan(20) from dual;

    ?TANH(20)?? TAN(20)
    --------- ---------
    ??????? 1 2.2371609

    ?

    35.TRUNC
    按照指定的精度截取一個(gè)數(shù)
    SQL> select trunc(124.1666,-2) trunc1,trunc(124.16666,2) from dual;

    ?? TRUNC1 TRUNC(124.16666,2)
    --------- ------------------
    ????? 100???????????? 124.16

    ?

    36.ADD_MONTHS
    增加或減去月份
    SQL> select to_char(add_months(to_date('199912','yyyymm'),2),'yyyymm') from dual;

    TO_CHA
    ------
    200002
    SQL> select to_char(add_months(to_date('199912','yyyymm'),-2),'yyyymm') from dual;

    TO_CHA
    ------
    199910


    37.LAST_DAY
    返回日期的最后一天
    SQL> select to_char(sysdate,'yyyy.mm.dd'),to_char((sysdate)+1,'yyyy.mm.dd') from dual;

    TO_CHAR(SY TO_CHAR((S
    ---------- ----------
    2004.05.09 2004.05.10
    SQL> select last_day(sysdate) from dual;

    LAST_DAY(S
    ----------
    31-5月 -04


    38.MONTHS_BETWEEN(date2,date1)
    給出date2-date1的月份
    SQL> select months_between('19-12月-1999','19-3月-1999') mon_between from dual;

    MON_BETWEEN
    -----------
    ????????? 9
    SQL>selectmonths_between(to_date('2000.05.20','yyyy.mm.dd'),to_date('2005.05.20','yyyy.mm.dd')) mon_betw from dual;

    ?MON_BETW
    ---------
    ????? -60


    39.NEW_TIME(date,'this','that')
    給出在this時(shí)區(qū)=other時(shí)區(qū)的日期和時(shí)間
    SQL> select to_char(sysdate,'yyyy.mm.dd hh24:mi:ss') bj_time,to_char(new_time
    ? 2? (sysdate,'PDT','GMT'),'yyyy.mm.dd hh24:mi:ss') los_angles from dual;

    BJ_TIME???????????? LOS_ANGLES
    ------------------- -------------------
    2004.05.09 11:05:32 2004.05.09 18:05:32


    40.NEXT_DAY(date,'day')
    給出日期date和星期x之后計(jì)算下一個(gè)星期的日期
    SQL> select next_day('18-5月-2001','星期五') next_day from dual;

    NEXT_DAY
    ----------
    25-5月 -01

    ?

    41.SYSDATE
    用來(lái)得到系統(tǒng)的當(dāng)前日期
    SQL> select to_char(sysdate,'dd-mm-yyyy day') from dual;

    TO_CHAR(SYSDATE,'
    -----------------
    09-05-2004 星期日
    trunc(date,fmt)按照給出的要求將日期截?cái)?如果fmt='mi'表示保留分,截?cái)嗝?br />SQL> select to_char(trunc(sysdate,'hh'),'yyyy.mm.dd hh24:mi:ss') hh,
    ? 2? to_char(trunc(sysdate,'mi'),'yyyy.mm.dd hh24:mi:ss') hhmm from dual;

    HH????????????????? HHMM
    ------------------- -------------------
    2004.05.09 11:00:00 2004.05.09 11:17:00

    ?

    42.CHARTOROWID
    將字符數(shù)據(jù)類(lèi)型轉(zhuǎn)換為ROWID類(lèi)型
    SQL> select rowid,rowidtochar(rowid),ename from scott.emp;

    ROWID????????????? ROWIDTOCHAR(ROWID) ENAME
    ------------------ ------------------ ----------
    AAAAfKAACAAAAEqAAA AAAAfKAACAAAAEqAAA SMITH
    AAAAfKAACAAAAEqAAB AAAAfKAACAAAAEqAAB ALLEN
    AAAAfKAACAAAAEqAAC AAAAfKAACAAAAEqAAC WARD
    AAAAfKAACAAAAEqAAD AAAAfKAACAAAAEqAAD JONES


    43.CONVERT(c,dset,sset)
    將源字符串 sset從一個(gè)語(yǔ)言字符集轉(zhuǎn)換到另一個(gè)目的dset字符集
    SQL> select convert('strutz','we8hp','f7dec') "conversion" from dual;

    conver
    ------
    strutz


    44.HEXTORAW
    將一個(gè)十六進(jìn)制構(gòu)成的字符串轉(zhuǎn)換為二進(jìn)制


    45.RAWTOHEXT
    將一個(gè)二進(jìn)制構(gòu)成的字符串轉(zhuǎn)換為十六進(jìn)制

    ?

    46.ROWIDTOCHAR
    將ROWID數(shù)據(jù)類(lèi)型轉(zhuǎn)換為字符類(lèi)型

    ?

    47.TO_CHAR(date,'format')
    SQL> select to_char(sysdate,'yyyy/mm/dd hh24:mi:ss') from dual;

    TO_CHAR(SYSDATE,'YY
    -------------------
    2004/05/09 21:14:41

    ?

    48.TO_DATE(string,'format')
    將字符串轉(zhuǎn)化為ORACLE中的一個(gè)日期


    49.TO_MULTI_BYTE
    將字符串中的單字節(jié)字符轉(zhuǎn)化為多字節(jié)字符
    SQL>? select to_multi_byte('高') from dual;

    TO
    --


    50.TO_NUMBER
    將給出的字符轉(zhuǎn)換為數(shù)字
    SQL> select to_number('1999') year from dual;

    ???? YEAR
    ---------
    ???? 1999


    51.BFILENAME(dir,file)
    指定一個(gè)外部二進(jìn)制文件
    SQL>insert into file_tb1 values(bfilename('lob_dir1','image1.gif'));


    52.CONVERT('x','desc','source')
    將x字段或變量的源source轉(zhuǎn)換為desc
    SQL> select sid,serial#,username,decode(command,
    ? 2? 0,'none',
    ? 3? 2,'insert',
    ? 4? 3,
    ? 5? 'select',
    ? 6? 6,'update',
    ? 7? 7,'delete',
    ? 8? 8,'drop',
    ? 9? 'other') cmd? from v$session where type!='background';

    ????? SID?? SERIAL# USERNAME?????????????????????? CMD
    --------- --------- ------------------------------ ------
    ??????? 1???????? 1??????????????????????????????? none
    ??????? 2???????? 1??????????????????????????????? none
    ??????? 3???????? 1??????????????????????????????? none
    ??????? 4???????? 1??????????????????????????????? none
    ??????? 5???????? 1??????????????????????????????? none
    ??????? 6???????? 1??????????????????????????????? none
    ??????? 7????? 1275??????????????????????????????? none
    ??????? 8????? 1275??????????????????????????????? none
    ??????? 9??????? 20 GAO??????????????????????????? select
    ?????? 10??????? 40 GAO??????????????????????????? none


    53.DUMP(s,fmt,start,length)
    DUMP函數(shù)以fmt指定的內(nèi)部數(shù)字格式返回一個(gè)VARCHAR2類(lèi)型的值
    SQL> col global_name for a30
    SQL> col dump_string for a50
    SQL> set lin 200
    SQL> select global_name,dump(global_name,1017,8,5) dump_string from global_name;

    GLOBAL_NAME??????????????????? DUMP_STRING
    ------------------------------ --------------------------------------------------
    ORACLE.WORLD?????????????????? Typ=1 Len=12 CharacterSet=ZHS16GBK: W,O,R,L,D


    54.EMPTY_BLOB()和EMPTY_CLOB()
    這兩個(gè)函數(shù)都是用來(lái)對(duì)大數(shù)據(jù)類(lèi)型字段進(jìn)行初始化操作的函數(shù)


    55.GREATEST
    返回一組表達(dá)式中的最大值,即比較字符的編碼大小.
    SQL> select greatest('AA','AB','AC') from dual;

    GR
    --
    AC
    SQL> select greatest('啊','安','天') from dual;

    GR
    --


    56.LEAST
    返回一組表達(dá)式中的最小值
    SQL> select least('啊','安','天') from dual;

    LE
    --


    57.UID
    返回標(biāo)識(shí)當(dāng)前用戶(hù)的唯一整數(shù)
    SQL> show user
    USER 為"GAO"
    SQL> select username,user_id from dba_users where user_id=uid;

    USERNAME???????????????????????? USER_ID
    ------------------------------ ---------
    GAO?????????????????????????????????? 25

    ?

    58.USER
    返回當(dāng)前用戶(hù)的名字
    SQL> select user from? dual;

    USER
    ------------------------------
    GAO


    59.USEREVN
    返回當(dāng)前用戶(hù)環(huán)境的信息,opt可以是:
    ENTRYID,SESSIONID,TERMINAL,ISDBA,LABLE,LANGUAGE,CLIENT_INFO,LANG,VSIZE
    ISDBA? 查看當(dāng)前用戶(hù)是否是DBA如果是則返回true
    SQL> select userenv('isdba') from dual;

    USEREN
    ------
    FALSE
    SQL> select userenv('isdba') from dual;

    USEREN
    ------
    TRUE
    SESSION
    返回會(huì)話(huà)標(biāo)志
    SQL> select userenv('sessionid') from dual;

    USERENV('SESSIONID')
    --------------------
    ???????????????? 152
    ENTRYID
    返回會(huì)話(huà)人口標(biāo)志
    SQL> select userenv('entryid') from dual;

    USERENV('ENTRYID')
    ------------------
    ???????????????? 0
    INSTANCE
    返回當(dāng)前INSTANCE的標(biāo)志
    SQL> select userenv('instance') from dual;

    USERENV('INSTANCE')
    -------------------
    ????????????????? 1
    LANGUAGE
    返回當(dāng)前環(huán)境變量
    SQL> select userenv('language') from dual;

    USERENV('LANGUAGE')
    ----------------------------------------------------
    SIMPLIFIED CHINESE_CHINA.ZHS16GBK
    LANG
    返回當(dāng)前環(huán)境的語(yǔ)言的縮寫(xiě)
    SQL> select userenv('lang') from dual;

    USERENV('LANG')
    ----------------------------------------------------
    ZHS
    TERMINAL
    返回用戶(hù)的終端或機(jī)器的標(biāo)志
    SQL> select userenv('terminal') from dual;

    USERENV('TERMINA
    ----------------
    GAO
    VSIZE(X)
    返回X的大小(字節(jié))數(shù)
    SQL> select vsize(user),user from dual;

    VSIZE(USER) USER
    ----------- ------------------------------
    ????????? 6 SYSTEM

    ?

    60.AVG(DISTINCT|ALL)
    all表示對(duì)所有的值求平均值,distinct只對(duì)不同的值求平均值
    SQLWKS> create table table3(xm varchar(8),sal number(7,2));
    語(yǔ)句已處理。
    SQLWKS>? insert into table3 values('gao',1111.11);
    SQLWKS>? insert into table3 values('gao',1111.11);
    SQLWKS>? insert into table3 values('zhu',5555.55);
    SQLWKS> commit;

    SQL> select avg(distinct sal) from gao.table3;

    AVG(DISTINCTSAL)
    ----------------
    ???????? 3333.33

    SQL> select avg(all sal) from gao.table3;

    AVG(ALLSAL)
    -----------
    ??? 2592.59


    61.MAX(DISTINCT|ALL)
    求最大值,ALL表示對(duì)所有的值求最大值,DISTINCT表示對(duì)不同的值求最大值,相同的只取一次
    SQL> select max(distinct sal) from scott.emp;

    MAX(DISTINCTSAL)
    ----------------
    ??????????? 5000


    62.MIN(DISTINCT|ALL)
    求最小值,ALL表示對(duì)所有的值求最小值,DISTINCT表示對(duì)不同的值求最小值,相同的只取一次
    SQL> select min(all sal) from gao.table3;

    MIN(ALLSAL)
    -----------
    ??? 1111.11


    63.STDDEV(distinct|all)
    求標(biāo)準(zhǔn)差,ALL表示對(duì)所有的值求標(biāo)準(zhǔn)差,DISTINCT表示只對(duì)不同的值求標(biāo)準(zhǔn)差
    SQL> select stddev(sal) from scott.emp;

    STDDEV(SAL)
    -----------
    ? 1182.5032

    SQL> select stddev(distinct sal) from scott.emp;

    STDDEV(DISTINCTSAL)
    -------------------
    ?????????? 1229.951

    ?

    64.VARIANCE(DISTINCT|ALL)
    求協(xié)方差

    SQL> select variance(sal) from scott.emp;

    VARIANCE(SAL)
    -------------
    ??? 1398313.9


    65.GROUP BY
    主要用來(lái)對(duì)一組數(shù)進(jìn)行統(tǒng)計(jì)
    SQL> select deptno,count(*),sum(sal) from scott.emp group by deptno;

    ?? DEPTNO? COUNT(*)? SUM(SAL)
    --------- --------- ---------
    ?????? 10???????? 3????? 8750
    ?????? 20???????? 5???? 10875
    ?????? 30???????? 6????? 9400

    ?

    66.HAVING
    對(duì)分組統(tǒng)計(jì)再加限制條件
    SQL> select deptno,count(*),sum(sal) from scott.emp group by deptno having count(*)>=5;

    ?? DEPTNO? COUNT(*)? SUM(SAL)
    --------- --------- ---------
    ?????? 20???????? 5???? 10875
    ?????? 30???????? 6????? 9400
    SQL> select deptno,count(*),sum(sal) from scott.emp having count(*)>=5 group by deptno ;

    ?? DEPTNO? COUNT(*)? SUM(SAL)
    --------- --------- ---------
    ?????? 20???????? 5???? 10875
    ?????? 30???????? 6????? 9400


    67.ORDER BY
    用于對(duì)查詢(xún)到的結(jié)果進(jìn)行排序輸出
    SQL> select deptno,ename,sal from scott.emp order by deptno,sal desc;

    ?? DEPTNO ENAME??????????? SAL
    --------- ---------- ---------
    ?????? 10 KING??????????? 5000
    ?????? 10 CLARK?????????? 2450
    ?????? 10 MILLER????????? 1300
    ?????? 20 SCOTT?????????? 3000
    ?????? 20 FORD??????????? 3000
    ?????? 20 JONES?????????? 2975
    ?????? 20 ADAMS?????????? 1100
    ?????? 20 SMITH??????????? 800
    ?????? 30 BLAKE?????????? 2850
    ?????? 30 ALLEN?????????? 1600
    ?????? 30 TURNER????????? 1500
    ?????? 30 WARD??????????? 1250
    ?????? 30 MARTIN????????? 1250
    ?????? 30 JAMES??????????? 950


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