Posted on 2009-09-25 15:47
fd 閱讀(1688)
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第二篇：個人方法：
1.
返回List，
.setResultTransformer(
Transformers.ALIAS_TO_ENTITY_MAP);將結果轉為Map，存放到list中，即list中為若干map對象；
獲取可按此方法：
for (int i = 0; i < list.size(); i++) {
Map map = (Map) list.get(i);
System.out.println(map.get("table_colum_name"));
}
在jsp頁面，可用S標簽獲取
<s:property value="table_colum_name" />
public List getDamTestType(Integer damId) throws Exception {
List list = new ArrayList();
Session session = null;
Transaction tx = null;
String strSql1 = "";
strSql1 = "select distinct testType.id,testType.mc from [" + damId + "_lb] as testType "
+ "inner join [" + damId + "_jcxm] as testObj on testObj.lbgl_id=testType.id "
+ "inner join [" + damId + "_cd] as testSite on testSite.jcxm_id=testObj.id "
+ "inner join [" + damId + "_sctj] as upLoadCond on upLoadCond.cd_id=testSite.id ";
try {
session = HibernateSessionFactory.getSession();
tx = session.beginTransaction();
Query query = session.createSQLQuery(strSql1).setResultTransformer(
Transformers.ALIAS_TO_ENTITY_MAP);
list = query.list();
tx.commit();
} catch (Exception e) {
e.printStackTrace();
tx.rollback();
throw e;
} finally {
session.close();
}
return list;
}
下次再寫。。。