mysql> UPDATE EACONTACTGROUPS A
SET GROUPNAME=(SELECT
CONCAT(B.GROUPNAME,'-',A.GROUPNAME) FROM EACONTACTGROUPS B WHERE
B.CORPID=A.CORPID AND B.USERID=A.USERID AND B.GROUPID=A.PARENTGROUPID)
WHERE A.PARENTGROUPID IS NOT NULL;
ERROR 1093 (HY000): You can't specify target table 'A' for update in FROM clause
上面是目前MYSQL5.0仍然有的限制，文檔中說：
In general, you cannot modify a table and
select from the same table in a subquery. For example, this limitation
applies to statements of the following forms:
DELETE FROM t WHERE ... (SELECT ... FROM t
...);UPDATE t ... WHERE col = (SELECT ... FROM t ...);{INSERT|REPLACE}
INTO t (SELECT ... FROM t ...);
Exception: The preceding prohibition does not apply if you are using a subquery for the modified table in the
FROM
clause. Example:
UPDATE t ... WHERE col = (SELECT (SELECT ... FROM t...) AS _t ...);
Here the prohibition does not apply because a subquery in the
FROM
clause is materialized as a temporary table, so the relevant rows in
t
have already been selected by the time the update to
t
takes place. 依據文檔，改成下面的樣子就行了：
mysql> UPDATE EACONTACTGROUPS A
SET GROUPNAME=(SELECT
CONCAT(B.GROUPNAME,'-',A.GROUPNAME) FROM ( SELECT
GROUPNAME,CORPID,USERID,GROUPID,PARENTGROUPID FROM EACONTACTGROUPS) B
WHERE B.CORPID=A.CORPID AND B.USERID=A.USERID AND B.GROUPID=A.PARENTGROUPID)
WHERE A.PARENTGROUPID IS NOT NULL;
Query OK, 16 rows affected (0.01 sec)
Rows matched: 16 Changed: 16 Warnings: 0
注:今天寫一個刪除語句時找到的一點資料.解決了一個簡單的刪除語句.呵呵,以后注意了,
原句:delete from menu_item where parent_id =(select menu_item_id from menu_item where menu_data like '%manageVendors%');
修改后:delete from
menu_item where parent_id =(select temp.menu_item_id from (select
m.menu_item_id,m.menu_data from menu_item m) temp where temp.menu_data
like '%manageVendors%');