有的時候需要對數組里的element進行排序。當然可以自己編寫合適的排序方法,但既然java包里有自帶的Arrays.sort排序方法,在數組元素比較少的時候為何不用?
Sorting an Array
1. 數字排序?
int[] intArray = new int[] {
4, 1, 3, -23
};
Arrays.sort(intArray);
輸出: [-23, 1, 3, 4]
2. 字符串排序,先大寫后小寫
String[] strArray = new String[] {
"z", "a", "C"
};
Arrays.sort(strArray);
輸出: [C, a, z]
3. 嚴格按字母表順序排序,也就是忽略大小寫排序 Case-insensitive sort
Arrays.sort(strArray, String.CASE_INSENSITIVE_ORDER);
輸出: [a, C, z]
4. 反向排序, Reverse-order sort
Arrays.sort(strArray, Collections.reverseOrder());
輸出:[z, a, C]
5. 忽略大小寫反向排序 Case-insensitive reverse-order sort
Arrays.sort(strArray, String.CASE_INSENSITIVE_ORDER);
Collections.reverse(Arrays.asList(strArray));
輸出: [z, C, a]
java初學者最常見的錯誤思想,就是試圖去寫一些方法來完成數組的排序功能,其實,數組排序功能,在java的api里面早已實現,我們沒有必要去重復制造輪子。
Arrays類有一個靜態方法sort,利用這個方法我們可以傳入我們要排序的數組進去排序,因為我們傳入的是一個數組的引用,所以排序完成的結果也通過這個引用的來更改數組.對于整數、字符串排序,jdk提供了默認的實現,如果要對一個對象數組排序,則要自己實現java.util.Comparator接口。
package demo1.client;
import java.util.Arrays;
import java.util.Comparator;
public class ArraySortDemo {
???
??? public void
sortIntArray() {
???
??? int[]
arrayToSort = new int[] { 48, 5, 89, 80, 81, 23, 45, 16, 2 };
???
???
System.out.println("排序前");
???
??? for (int i =
0; i < arrayToSort.length; i++)
???
???
???
System.out.println(arrayToSort[i]);
???
??? //
調用數組的靜態排序方法sort
???
???
Arrays.sort(arrayToSort);
???
???
System.out.println("排序后");
???
??? for (int i =
0; i < arrayToSort.length; i++)
???
???
???
System.out.println(arrayToSort[i]);
??? }
???
??? public void
sortStringArray() {
???
??? String[]
arrayToSort = new String[] { "Oscar", "Charlie", "Ryan",
???
???
???
??? "Adam",
"David" };
???
???
System.out.println("排序前");
???
??? for (int i =
0; i < arrayToSort.length; i++)
???
???
???
System.out.println(arrayToSort[i]);
???
???
System.out.println("排序后");
???
???
//調用數組的靜態排序方法sort
???
???
Arrays.sort(arrayToSort);
???
??? for (int i =
0; i < arrayToSort.length; i++)
???
???
???
System.out.println(arrayToSort[i]);
??? }
???
??? public void
sortObjectArray() {
???
??? Dog o1 = new
Dog("dog1", 1);
???
??? Dog o2 = new
Dog("dog2", 4);
???
??? Dog o3 = new
Dog("dog3", 5);
???
??? Dog o4 = new
Dog("dog4", 2);
???
??? Dog o5 = new
Dog("dog5", 3);
???
??? Dog[] dogs =
new Dog[] { o1, o2, o3, o4, o5 };
???
???
System.out.println("排序前");
???
??? for (int i =
0; i < dogs.length; i++) {
???
???
??? Dog dog =
dogs[i];
???
???
???
System.out.println(dog.getName());
???
??? }
???
???
Arrays.sort(dogs, new ByWeightComparator());
???
???
System.out.println("排序后:");
???
??