logic:iterate 里面的id和name写什么，对应哪里

MichaelLee — Mon, 13 Apr 2009 03:53:00 GMT

工号	姓名	工作	�q�限	工资

--------------------------------------------------------------------------------------------------

public class QueryAction extends Action {

public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {

EmpDao empDao = new EmpDao();
ArrayList list = empDao.empName();
//System.out.println(list);
request.setAttribute("list", list);

return new ActionForward("/display.jsp");
}
}

Java代码

"emp" name="list">

name属性：是你攄��Bean的集合，在你的这�D�代码中�Q?

Java代码

public class QueryAction extends Action {
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
EmpDao empDao = new EmpDao();
ArrayList list = empDao.empName();
//System.out.println(list);
request.setAttribute("list", list);
return new ActionForward("/display.jsp");
}
}

public class QueryAction extends Action {
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
EmpDao empDao = new EmpDao();
ArrayList list = empDao.empName();
//System.out.println(list);
request.setAttribute("list", list);
return new ActionForward("/display.jsp");
}
}

Java代码

request.setAttribute("list", list);

request.setAttribute("list", list);

你是��list攑օ�到request范围内，对应的名字是list�Q�如果你要是写成

Java代码

request.setAttribute("myList", list);

request.setAttribute("myList", list);

,那么�Q�logic:iterator中的name属性就要�ؓ"myList"�Q?
logic:iterator中的id属性，其实是你要从你的集合中取出的Bean的名字，�q�个名字是�Q意�v的，主要是下面的标签中的name属性要跟logic:iterator中的id属性对应上�Q�其实这里的是这��L��Q�首�?lt;logic:iterator>标签会把name属性��gؓlist的集合里的bean逐一取出来，每取出来一个，��把他存到名为id属性的值的pageContext范围内，一看代码你��p��明白�Q?
主要代码�Q?

Java代码

//首先取出List�Q�getAttribute()�Ҏ��中的值就�?lt;logic:iterator>标签的name
//�?
List list=request.getAttribute("list");
//然后把取出来的bean存入pageContext范围内，对应的名字就是id的�?
pageContext.setAttribute("emp",bean);
//标签其实��是利用反射把Bean从相应的范围内取�?
pageContext.getAttribute("emp");

MichaelLee 2009-04-13 11:53 发表评论

MichaelLee — Wed, 25 Mar 2009 16:10:00 GMT

1.�~�写相应的异常类�Q?br /> 2.捕捉相应的异常类�Q�进行抛出，可以把该代码��装到相应的�Ҏ��中，比如在LoginDAO�q�个�c�M��Q�有个isLogin()�Ҏ��判断是否登陆成功�Q�同时根据需要抛出相应异常，如：UserNotFoundException、PasswordErrorException�{�。在LoginAction�q�个Action�c�M��调用LoginDAO�c�M��的isLogin()斚w��验证用户是否登陆成功�Q?br /> 3.在国际化资源文�g中，�~�写相应异常的key�Q�以及对于的value��|��

4.�?span class="hilite1">struts-config.xml中配�|�以上相关需要的信息�Q�同�Ӟ��配置标签�Q�指定相应的key�Q�type的属性，key值对应国际化资源文�g中异常的key��|��type��q��写的异常�c�R��同�Ӟ��在相应Action中配�|�input属性，该属性�ؓ出现异常时进行蟩转的��面。如�?lt;exception/>中配�|�path属性，则path属性优先于中的input属性�?br />
5.在需要显�C�错误提�C�的jsp��面�?lt;html:errors/>标签�q�行错误信息��d��?

LoginDAO�c�：

Java代码

public class LoginDAO {
public void isLogin(String username,String password){
if(!(username.equals("admin"))){
throw "COLOR: #ff0000">new UserNotFoundException();
//事先声明的异常类
}
else if(!(password.equals("admin"))){
throw "COLOR: #ff0000">new PasswordErrorException()
;//事先声明的异常类
}
}
}
"COLOR: #ff0000">LoginAction�c�：
package wiki.struts;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.DynaActionForm;
public class LoginAction extends Action {
@Override
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
DynaActionForm daf = (DynaActionForm)form;
String username = (String)daf.get("username");
String password = (String)daf.get("password");
LoginDAO loginDAO = new LoginDAO();
loginDAO.isLogin(username, password);
return mapping.findForward("success");
}
}

public class LoginDAO {
public void isLogin(String username,String password){
if(!(username.equals("admin"))){
throw new UserNotFoundException();
//事先声明的异常类
}
else if(!(password.equals("admin"))){
throw new PasswordErrorException()
;//事先声明的异常类
}
}
}
LoginAction�c�：

package wiki.struts;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.DynaActionForm;
public class LoginAction extends Action {
@Override
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
DynaActionForm daf = (DynaActionForm)form;
String username = (String)daf.get("username");
String password  = (String)daf.get("password");
LoginDAO loginDAO = new LoginDAO();
loginDAO.isLogin(username, password);
return mapping.findForward("success");
}
}

struts-config.xml中的部分配置

Xml代码

<action-mappings>
<action path="/login" type="wiki.struts.LoginAction"
name="loginForm" scope="request" <SPAN style="COLOR: #ff0000">input="/login.jsp"SPAN>
>
<SPAN style="COLOR: #ff0000"><exception key="login.user.name.error"
type="wiki.struts.UserNotFoundException" path="/login_error.jsp" />
<exception key="login.user.password.error"
type="wiki.struts.PasswordErrorException" path="/login_error.jsp" />SPAN>
<forward name="success" path="/login_success.jsp" />
action>


struts.LoginAction"
name="loginForm" scope="request" input="/login.jsp"
>
struts.UserNotFoundException"   path="/login_error.jsp" />
struts.PasswordErrorException" path="/login_error.jsp" />

MichaelLee 2009-03-26 00:10 发表评论

亚洲AV日韩精品久久久久久久,国产亚洲高清在线精品不卡,亚洲网站在线免费观看

logic:iterate 里面的id和name写什么，对应哪里