true_star — Tue, 21 Apr 2009 05:31:00 GMT

最�q�的一个项目又要用到webservice�Q�axis�Q�，上次��Z��赶时间完成�Q务，��单的找了些例子然后就�q�样用了�Q�还好项目里本来��有对象和xml之间转换的接口，所以要传的对象一律�{换成xml�Q�然后传字符丌Ӏ?br /> ��试了N久才搞定了传输属性不是基本数据类型的问题。简单帖个代码：

1.server-config.wsdd

<service name="sendUser" provider="java:RPC">

      <parameter name="allowedMethods" value="getUserByUserId"/>
      <parameter name="className" value="cn.gov.zjport.suzhou.webservice.GetUser4WebServiceImpl"/>
      <beanMapping languageSpecificType="java:cn.gov.zjport.suzhou.domain.CustomUser"  qname="ns:CustomUser" xmlns:ns="urn:GetUser4WebService"/>
      <beanMapping languageSpecificType="java:cn.gov.zjport.suzhou.domain.CustomRole"  qname="ns:CustomRole" xmlns:ns="urn:GetUser4WebService"/>
      <beanMapping languageSpecificType="java:cn.gov.zjport.suzhou.domain.CustomUserRole"  qname="ns:CustomUserRole" xmlns:ns="urn:GetUser4WebService"/>
service>

2.客户端测试代�?

QName qn = new QName("urn:GetUser4WebService","CustomUser");
             QName qn1 = new QName("urn:GetUser4WebService","CustomRole");
             QName qn2 = new QName("urn:GetUser4WebService","CustomUserRole");
             call.setTargetEndpointAddress(new URL("http://localhost:8080/suzhouPlatform/webServices/sendUser") );
             call.setOperationName(new QName("http://localhost:8080/suzhouPlatform/webServices/sendUser","getUserByUserId"));
             call.registerTypeMapping(CustomUser.class, qn,new BeanSerializerFactory(CustomUser.class, qn),new BeanDeserializerFactory(CustomUser.class, qn));
             call.registerTypeMapping(CustomRole.class, qn1,new BeanSerializerFactory(CustomRole.class, qn1),new BeanDeserializerFactory(CustomRole.class, qn1));
             call.registerTypeMapping(CustomUserRole.class, qn2,new BeanSerializerFactory(CustomUserRole.class, qn2),new BeanDeserializerFactory(CustomUserRole.class, qn2));
             Object result = call.invoke(new String[]{"admin"});

大概代码��p��样了^_^

true_star 2009-04-21 13:31 发表评论

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