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amenglai — Thu, 09 Aug 2012 05:50:00 GMT

CREATE TABLE report

( id NUMBER(2),

year NUMBER(4),

month NUMBER(2),

amt NUMBER(3)) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 1, 110 ) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 2, 120) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 3, 130) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 4, 140) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 5, 150) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 6, 160) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 7, 170) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 8, 180) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 9, 190) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 10, 100) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 11, 110) ;

INSERT INTO report( id, year, month, amt ) VALUES(1, 2011, 12, 110) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 1, 110 ) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 2, 120) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 3, 130) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 4, 140) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 5, 150) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 6, 160) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 7, 170) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 8, 180) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 9, 190) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 10, 100) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 11, 110) ;

INSERT INTO report( id, year, month, amt ) VALUES(2, 2012, 12, 110) ;

-- 逐��汇�?/span>

select id, year, month, sum(amt)

from report

group by rollup( id, year, month ) ;

ID YEAR MONTH SUM(AMT)

---------- ---------- ---------- ----------

1 2011 1 220

1 2011 2 240

1 2011 3 260

1 2011 4 280

1 2011 5 300

1 2011 6 320

1 2011 7 340

1 2011 8 360

1 2011 9 380

1 2011 10 200

1 2011 11 220

1 2011 12 220

1 2011 3340 -- 1, 2011, ��计

1 3340 -- 1, ��计

2 2012 1 110

2 2012 2 120

2 2012 3 130

2 2012 4 140

2 2012 5 150

2 2012 6 160

2 2012 7 170

2 2012 8 180

2 2012 9 190

2 2012 10 100

2 2012 11 110

2 2012 12 110

2 2012 1670 -- 2, 2012, ��计

2 1670 -- 2, ��计

5010 -- 1+2, 总计

如果只要每年的小�?/span>, SQL如下

select *

from (

select id, year, month, sum(amt)

from report

group by rollup( id, year, month ) )

where id is not null

and year is not null ;

ID YEAR MONTH SUM(AMT)

---------- ---------- ---------- ----------

1 2011 1 220

1 2011 2 240

1 2011 3 260

1 2011 4 280

1 2011 5 300

1 2011 6 320

1 2011 7 340

1 2011 8 360

1 2011 9 380

1 2011 10 200

1 2011 11 220

1 2011 12 220

1 2011 3340

2 2012 1 110

2 2012 2 120

2 2012 3 130

2 2012 4 140

2 2012 5 150

2 2012 6 160

2 2012 7 170

2 2012 8 180

2 2012 9 190

2 2012 10 100

2 2012 11 110

2 2012 12 110

2 2012 1670

amenglai 2012-08-09 13:50 发表评论

amenglai — Mon, 23 May 2011 06:00:00 GMT

最�q�一�D�|��间在�?个模块代码的refactor。一个模块是因�ؓ(f��)性能的原因，另一个模块是因�ؓ(f��)很烂的数据库设计�Q�导致数据很隄��护，�q�且也会(x��)有潜在的性能问题�?br />有很多的感想�Q?br />1. 既然要做refactor�Q�就意味原来的代码肯定有很大的缺陗��但是即使这��P��也要先明��refactor的范围。而不是全部上来都做refactor�Q�那样会(x��)��D��refactor不可控。同时还要区分哪些是refactor�Q�哪些是new feature�Q�不要�؜在一赗��?br />2. test case很重要�?br />3. 详细的文档比代码实现更重要。时间上应该�?�Q?
4. 文档应包括：(x��)
A �Ҏ(gu��)��pȝ��业务逻辑的分析，以及(qi��ng)存在的问�?br /> B 新系�l�业务逻辑的分析，对应的改善方�?br /> C new design�Q�DB�Q?architecture
D 旧有�pȝ��需要改善的功能�?br />5. 再烂的系�l�也不是一无是处，所以尽量不要全盘否定�?br />

amenglai 2011-05-23 14:00 发表评论

win7 下安�?Microsoft Web Application Stress Tool

amenglai — Fri, 22 Apr 2011 08:10:00 GMT

在网上找�?ji��n)N多个版本�Q�哎�Q�害人啊�?br /> 主要问题��是msvcp50.dll�Q�这个dll文�g�Q�在win7里已�l�木有了(ji��n)�?br /> 解决��h��也很��单：(x��)
1 先安装WAS�Q�报错：(x��)

2 把msvcp50.dll拯��到安装�\径下�Q�再启动hclient.exe�Q�会(x��)提示重新安装�Q�按着提示再做一遍就好了(ji��n)�?/p>

amenglai 2011-04-22 16:10 发表评论